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Question:
A spring with constant 50 N/m is stretch 0.5 m. How much EPE does it have? A. 25 J B. 12.5 J C. 50 J D. 6.25 J
Answer:
Answer:
D. 6.25 J
Explanation:
EPE = 1/2*k*(Δx)²
∴ k = 50 N/m
∴ Δx = 0.5 m
⇒ EPE = 1/2*50 N/m*(0.5m)²
⇒ EPE = 6.25 N.m = 6.25 J
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