# Evaluate the function for the indicated values of x. function f(−10) = f(2) = f(−5) = f(−1) = f(8) =

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## Question: f(−10)

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To find f(-10) we choose a function that has x value -10

-10 <= -5 so we use f(x) = 2x + 1

Plug in -10 for x

f(-10) = 2(-10) +1 = -20 +1 = -19 So f(-10) = -19

Now find f(2)

2 lies between -5 and 5 so we use f(x) = x^2

f(x) f(2) = 4 . so f(2) = 4

f(−5)

-5 is equal to -5 so we use f(x) = 2x + 1

f(-5) = 2(-5) + 1 = -10 + 1 = -9

So f(-5) = -9

f(−1)

-1 lies between -5 and 5 so we use f(x)= READ MORE :  Controlled intersections use some form of which of the following?

f(-1)= = 1 so f(-1) = 1

f(8)

8 is greater than 5 so we use f(x) = 3 – x

f(8) = 3 – 8 = -5 so f(8) = -5

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