How many moles of gallium chlorate, Ga(ClO3)3, must react in order to produce 674 kJ of energy according to the following reaction? 2 Ga(ClO3)3 à 2 GaCl3 + 9 O2 DH = – 130.4 kJ

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Question:

How many moles of gallium chlorate, Ga(ClO3)3, must react in order to produce 674 kJ of energy according to the following reaction? 2 Ga(ClO3)3 à 2 GaCl3 + 9 O2 DH = – 130.4 kJ

Answer:

Answer:

10.3 mol Ga(ClO₃)₃

Explanation:

Let’s consider the following balanced thermochemical equation.

2 Ga(ClO₃)₃(s) ⇒ 2 GaCl₃(s) + 9 O₂(s)  ΔH = – 130.4 kJ

According to the balanced thermochemical equation, 130.4 kJ of heat are released when 2 moles of gallium chlorate react. The number of moles of gallium chlorate that must react to produce 674 kJ of energy is:

674 kJ × 2 mol Ga(ClO₃)₃/130.4 kJ = 10.3 mol Ga(ClO₃)₃

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