Molar mass of KAl(SO4)^2·12H2O

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Question:

Molar mass of KAl(SO4)^2·12H2O

Answer:

The molar mass of KAl(SO₄)₂.12H₂O is 474 g/mol

The molar mass of a compound is simply the sum of the molar masses of the individual elements present in the compound.

The molar mass of KAl(SO₄)₂.12H₂O can be obtained as follow:

Molar mass of Potassium, K = 39 g/mol

Molar mass of Aluminum, Al = 27 g/mol

Molar mass of Sulphur, S = 32 g/mol

Molar mass of Hydrogen, H = 1 g/mol

Molar mass of Oxygen, O = 16 g/mol

Molar mass of KAl(SO₄)₂.12H₂O =?

Molar mass of KAl(SO₄)₂.12H₂O = 39 + 27 + 2[32 + (16×4)] + 12[(2×1) + 16]

= 39 +27 + 2[32 + 64] + 12[2 + 16]

= 39 +27 + 2[96] + 12[18]

= 39 + 27 + 192 + 216

= 474 g/mol

Therefore, the molar mass of KAl(SO₄)₂.12H₂O is 474 g/mol

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