When the following equation is balanced with lowest whole-number coefficients, what is the coefficient for NO(g)? ___NH3(g) + ___O2(g) → ___NO(g) + ___H2O(g)

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Question:

When the following equation is balanced with lowest whole-number coefficients, what is the coefficient for NO(g)? ___NH3(g) + ___O2(g) → ___NO(g) + ___H2O(g)

Answer:

Answer:

Coefficient in front of the ?f=NO in the balanced equation – 4

Explanation:

The unbalanced reaction is shown below as:-

?f=NH 3%2BO 2%5Crightarrow%20NO%2BH 2O

On the left hand side,  

There are 1 nitrogen atom and 3 hydrogen atoms and 3 oxygen atoms

On the right hand side,  

There are 1 nitrogen atom and 2 hydrogen atoms and 2 oxygen atoms

Thus,  

Right side, ?f=H 2O must be multiplied by 6 and ?f=NO by 4

Left side, ?f=O 2 is multiplied by 5 and ?f=NH 3 by 4 so to balance the whole reaction.

Thus, the balanced reaction is:-

?f=4NH 3%2B5O 2%5Crightarrow%204NO%2B6H 2O

Coefficient in front of the ?f=NO in the balanced equation – 4

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